2 solutions for, solve cos x = -1/2? Answer sheet displays only one, does this mean there is only one?
It depends upon the range answers are allowed in. If you allow <0,2pi), there are certainly two answers as you say:frac2pi3 & frac4pi3. The range of arccos is often restricted ...

Bạn đang xem: Find the principal solution of cos x =

How bởi you find the exact value of displaystylesinleft(fracx2 ight) và displaystylecosleft(fracx2 ight) displaystylequad extifquadcosx=-frac14 ...
https://socratic.org/questions/how-do-you-find-the-exact-value-of-sin-x-2-and-cos-x-2-if-cos-x-1-4-and-pi-x-2pi
Nghi N. May 9, 2015 Use the trig identity:displaystylecosx=1-2sin^2left(fracx2 ight)displaystyle-frac14=1-2sin^2left(fracx2 ight) osin^2left(fracx2 ight)=frac58=0.625 ...
extLet cos^-10.8 = heta\ cos heta = 0.8 \ 1-2sin^2frac heta2 = 0.8 \ sin^2frac heta2 = 0.1 \ sinfrac heta2 = sqrt0.1 space ext(think about why it is not negative) \ sinleft(frac12cos^-10.8 ight) = sqrt0.1 ...
https://math.stackexchange.com/questions/1738848/find-the-number-of-solutions-of-the-equation-sin22x-cos28x-frac12-cos1
sin^2 2x-cos^2 8x=frac12 cos10x Use formula sin^2alpha=frac1-cos 2 alpha2; cos^2alpha=frac1+cos 2 alpha2 frac1-cos 4x2-frac1+cos 16x2=frac12 cos10x ...
https://math.stackexchange.com/questions/1449662/prove-that-the-equation-cos-x-x-1-2-0-has-a-unique-real-solution
An other way Let f(x)=cos(x)-frac12. |f(x)-f(y)|=|cos(x)-cos(y)|. Using the mean value theorem, we can show that |cos(x)-cos(y)|leq fracsqrt 22|x-y| & thus f is a ...

Xem thêm: Công Thức Hóa Học Của Ure - Công Thức Hóa Học Của Đạm Urê Là

https://math.stackexchange.com/questions/941509/finding-f-y-such-that-z-y-cosx-sim-mathcaln-0-sigma-for-x-sim-mathca
Suppose Y is exponentially distributed with expected value sigma so that Pr(Y>y)=e^-y/sigma, và let eginalign Z_1 & = sqrt-2log_e Y,cos X, \ Z_2 và =sqrt-2log_e Y,sin X. ...
More Items

left< eginarray l l 2 và 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 & 3 \ -1 & 1 và 5 endarray ight>

EnglishDeutschEspañolFrançaisItalianoPortuguêsРусский简体中文繁體中文Bahasa MelayuBahasa Indonesiaالعربية日本語TürkçePolskiעבריתČeštinaNederlandsMagyar Nyelv한국어SlovenčinaไทยελληνικάRomânăTiếng Việtहिन्दीঅসমীয়াবাংলাગુજરાતીಕನ್ನಡकोंकणीമലയാളംमराठीଓଡ଼ିଆਪੰਜਾਬੀதமிழ்తెలుగు